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Question

sin1x(1x2)3/4dx

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Solution

Let I=sin1x(1x2)3/4dx=sin1x(1x2)1x2dxPut sin1x=t11x2dx=dtand x=sin t1x2=cos2tcost=1x2 I=tcos2tdt

Using integration by parts,
I=tsec2t dt(ddtt.sec2tdt)dt=t.tanttan tdt=t.tant1.tan t dt=t.tant+log|cos t|+C [tan x dx=log|cosx|+C]=sin1x.x1x2+log|1x2|C


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