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Question

Integrate the function: cotxlog(sinx)

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Solution

Given: cotxlog(sinx).dx
Let log(sinx)=t
Differentiating both sides w.r.t.x
1sinxcosx=dtdxcotx dx=dt
On substituting
=tdt
=t22+C
=12[log(sinx)]2+C
Where C is constant of integration

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