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Question

Integrate the function.
x2exdx.

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Solution

Let I=x2exdx
On taking x2 as first function and ex as second function and integrating by parts, we get I=x2exdx[ddx(x2)exdx]dx=x2ex[2xex]dx
Again, integrating by parts, we get
I=x2ex{2xexdx2[ddx(x)exdx]dx}=x2ex2xex+2exdx=x2ex2xex+2ex+CI=ex(x22x+2)+C


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