CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Integrate the function.
x2exdx.

Open in App
Solution

Let I=x2exdx
On taking x2 as first function and ex as second function and integrating by parts, we get I=x2exdx[ddx(x2)exdx]dx=x2ex[2xex]dx
Again, integrating by parts, we get
I=x2ex{2xexdx2[ddx(x)exdx]dx}=x2ex2xex+2exdx=x2ex2xex+2ex+CI=ex(x22x+2)+C


flag
Suggest Corrections
thumbs-up
34
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon