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Question

Integrate the function x3ex

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Solution

Let I=x2exdx
Taking x2 as first function and ex as second function and integrating using by parts, we obtain
I=x2exdx{(ddxx2)exdx}dx
=x2ex2xexdx
=x2ex2[xexdx{(ddxx)exdx}dx]
=x2ex2[xexexdx]
=x2ex2[xexex]
=x2ex2xex+2ex+C
=ex(x22x+2)+C

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