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Action of Water on Calcium Carbide

Isobutyraldeh...

Question

Isobutyraldehyde on reaction with formaldehyde and $K_{2} C O_{3}$ gives compound $^{'} A^{'}$ . Compound $^{'} A^{'}$ reacts with $K C N$ and yields compound $^{'} B^{'}$ , which on hydrolysis gives a stable compound $^{'} C^{'}$ . The compond 'C' is

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Q. An organic compound (A) gives positive Liebermann reaction and on treatment with

C H C l_{3} / K O H

followed by hydrolysis gives (B) and (C) ,. Compound (B) gives colour with Schiff's reagent but not (C), which is steam - volatile. (C) on treatment with

L I A l H_{4}

C_{7} H_{8} O_{2}

which on oxidation gives 9E), Compound (E) reacts with

{(C H_{3} C O)}_{2} O / C H_{3} C O O H

to give a pain - reliever (F), Give structure of (A) to (F) with proper reasoning.

(A)

of boron reacts with

N M e_{3}

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(B)

which on hydrolysis gives a compound

(C)

and hydrogen gas. Compound

(C)

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C

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N M e_{3}

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B

which on hydrolysis gives a compound

C

D

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C

Q. An organic compound ‘A’ on reaction with

N H_{3}

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C (C_{8} H_{5} N O_{2})

. Compound C on sequential reaction with ethanolic KOH, alkyl chloride and hydrolysis with alkali gives a primary amine. The compound A is :

Q. Compound “A” on reduction with Sn/HCl gives “B” which on further reaction with

C H C l_{3}

and alcoholic KOH gives compound “C”. The compound upon hydrolysis gives aniline. The compound “A” is :

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Action of Water on Calcium Carbide

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