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Mixed Combination of Cells

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Question

It is possible to obtain a large potential difference by charging a number of capacitors in parallel and then disconnecting them to connect them again in series. What maximum potential difference can be obtained using $10$ capacitors each of $5 μ F$ and a charging source of $400 V$ ?

A

400 V

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B

1000 V

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C

4000 V

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D

2000 V

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Solution

The correct option is C $4000 V$

In parallel combination potential difference across all capacitors will be $400 V$ .

After connecting $10$ capacitors in series potential difference will get added and net potential difference will be $(400 V \times 10) = 4000 V$

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Mixed Combination of Cells

Standard XII Physics

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