Question

${\left(\frac{-3}{4}\right)}^2=?$

$\left(a\right)\frac{-9}{16}$

$\left(b\right)\frac{9}{16}$

$\left(c\right)\frac{16}{9}$

$\left(d\right)\frac{-16}{9}$

Answer 1

${\left(\frac{-3}{4}\right)}^2=\left(\frac{-3}{4}\right)\times \left(\frac{-3}{4}\right)=\frac{9}{16}$