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Question

Let a1,a2,a3 and a4 be in AP. If a1+a4=10 and a2a3=24, then the least term of them is

A
1
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B
2
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C
3
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D
4
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E
5
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Solution

The correct option is B 2
Let the four terms in an AP are (a3d),(ad),(a+d) and (a+3d).
Given, a1+a4=10
(a3d)+(a+3d)=10
2a=10a=5
and a2a3=24
(ad)(a+d)=24
(a2d2)=24
25d2=24
d2=1
Therefore, d=±1
When (d=1), then terms are : 2,4,6,8
and when (d=1), then terms are: 8,6,4,2.

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