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Question

Let a, b, c>0, a+b+c=15.
The least value of E=a3a2+ab+b2+b3b2+bc+c2+c3c2+ca+a2 is___


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Solution

Observe that
a3b3a2+ab+b2+b3c3b2+bc+c2+c3a3c2+ca+a2=(ab)+(bc)+(ca)=0Thus, we can writeE=12(a3+b3a2+ab+b2+b3+c3b2+bc+c2+c3+a3c2+ca+a2)But a3+b3a2+ab+b2a+b3Since a22ab+b2=(ab)20E13(a+b+c)=5


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