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Question

Let a=^i+4^j+2^k,b=3^i2^j+7^k and c=2^i^j+4^k. Find a vector d which is perpendicular to both a and b and c.d = 15

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Solution

The vector which is perpendicular to both a and b must be parallel to a×b.
Now, a×b=∣ ∣ ∣^i^j^k142327∣ ∣ ∣=^i(28+4)^j(76)+^k(212)=32^i^j14^k
Let d=λ(a×b)=λ(32^i^j14^k)
Also, c.d=15(2^i^j+4^k).λ(32^i^j14^k)=15
2×(32λ)+(1)×(λ)+4×(14λ)=1564λ+λ56λ=15λ=159=53
Required vector, d=53(32^i^j14^k)


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