Let A - x - x - R - x -1 - B - x - x - R - x -1- - 1 andA - B - R - D- then the set D isA- None of theseB- -x- 1-x - 2-C- -x- 1 - x-2-D- -x- 1 - x - 2-

The correct option is C A = x: nbsp;x nbsp;∈ R, 1 lt; x lt; 1 B = x: nbsp;x nbsp;∈ R:x 1 nbsp;≤ 1 or x 1 nbsp;≥ 1 nbsp; nbsp;= x : x ...

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Union

Let A = x : x...

Question

Let A = { x : x ∈ R, |x| < 1}; B = {x : x ∈ R, |x-1| ≥ 1} and

A ∪ B = R - D, then the set D is

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None of these

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Similar questions

A = [x ∶ x \in R, | x | < 1];

B = [x ∶ x \in R, | x - 1 | \geq 1]

A \cup B = R - D

D

A = {x : x \in R, | x | < 1}

B = {x : x \in R, | x - 1 | \geq 1}

A \cup B = R - D

D

Let $A = {x : x \in R, | x | < 1}$ ;
$B = {x : x \in R, | x - 1 | \geq 1}$ and

$A \cup B = R - D$ , then the set $D$ is

A = {x : x \in R, - 1 \leq x \leq 1}

B = {x : x \in R, | x | \leq 1}

A

B

Let $U = R ($ the set of all real numbers $)$ If $A = {x : x \in R, 0 < x < 2}, B = {x : x \in R, 1 < x \leq 3}$ , then

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