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Question

Let ¯r1,¯r2,¯r3..........¯rn, be the position vectors of points P1P2P3........Pn relative to the origin O. If the vector equation a1¯r1+a2¯r2+.........+an¯rn=0 holds, then a similar equation will also hold w.r.t. to any other origin provided:

A
a1+a2+......+an=n
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B
a1+a2+......+an=1
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C
a1+a2+......+an=0
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D
none
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Solution

The correct option is C a1+a2+......+an=0
Let the new origin be at c from previous origin.
So new position vectors are:
R1=r1c
R2=r2c
Rn=rnc
Now putting these new position vectors in the given vector equation:
a1(r1c)+a2(r2c)+.....+an(rnc)=(a1r1+a2r2+...+anrn)(a1+a2+...an)c=0(a1+a2+...an)c=(a1+a2+...an)c
For this vector equation to be zero. (a1+a2+...an)c has to be zero.
Also as c is non-zero (different origin) therefore (a1+a2+...an)=0

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