Equation of a Plane Passing through a Point and Perpendicular to a Given Vector
Let r̅̅1̅,r...
Question
Let ¯r1,¯r2,¯r3..........¯rn, be the position vectors of points P1′P2′P3′........Pn relative to the origin O. If the vector equation a1¯r1+a2¯r2+.........+an¯rn=0 holds, then a similar equation will also hold w.r.t. to any other origin provided:
A
a1+a2+......+an=n
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B
a1+a2+......+an=1
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C
a1+a2+......+an=0
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D
none
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Solution
The correct option is Ca1+a2+......+an=0 Let the new origin be at →c from previous origin. So new position vectors are: −→R1=→r1−→c −→R2=→r2−→c −→Rn=→rn−→c
Now putting these new position vectors in the given vector equation: a1(→r1−→c)+a2(→r2−→c)+.....+an(→rn−→c)=(a1→r1+a2→r2+...+an→rn)−(a1+a2+...an)→c=0−(a1+a2+...an)→c=−(a1+a2+...an)→c
For this vector equation to be zero. −(a1+a2+...an)→c has to be zero. Also as →c is non-zero (different origin) therefore (a1+a2+...an)=0