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Question

Let B1=3x+4y7=0&B24x3x14=0 are angle bisectors of the angle between the lines L1=0&L2=0 in which L1 is passes through the point (1,2) then

A
B1 is acute angle bisector
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B
B2 is acute angle bisector
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C
B1&B2 both are right angle bisector
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D
Data is insufficient
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Solution

The correct option is A B1 is acute angle bisector
Line L1 passes through point (1,2)
Let the perpendicular distance from Point (1,2) of given bisector B1:3x+4y7=0 is u then
u=∣ ∣3+8732+42∣ ∣
u=425u=45

Let the perpendicular distance from Point (1,2) of given bisector B2:4x3y14=0 is v then
v=∣ ∣462032+42∣ ∣
v=1625v=165
Here u<v then B1 is the acute angle bisector

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