Let f(x)=x(−1)[1x].x≠0, where [x] denotes the greatest integer less than or equal to x. then limx→0f(x)
Does not exist
is equal to 2
is equal to 0
is equal to -1
Since [1/x] is an integer . (−1)[1x]=±1
Hence f(x)=±x And limx→0f(x) = 0