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Identity (x+y)(x-y)

Let f(x)=√x²+...

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Let f(x)=√x²+2x+1 - √x²-2x+1 then value of f(-5/4)+f(3/4)+f(7/4) is equal to

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f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + s i n^{2} x & c o s^{2} x & 4 s i n 2 x s i n^{2} x & 1 + c o s^{2} x & 4 s i n 2 x s i n^{2} x & c o s^{2} x & 1 + 4 s i n 2 x \end{matrix} ∣ ∣ ∣ ∣ ∣

, then the maximum value of

f (x) =

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + {sin}^{2} x & {cos}^{2} x & 4 sin 2 x {sin}^{2} x & 1 + {cos}^{2} x & 4 sin 2 x {sin}^{2} x & {cos}^{2} x & 1 + 4 sin 2 x \end{matrix} ∣ ∣ ∣ ∣ ∣

, then the maximum value of

f (x) =

.

\frac{3 x - 1}{4} - \frac{2 x + 5}{3} = \frac{5}{2} - 2 x,

then the value of x is equal to :

f (x) = \frac{tan (\frac{π}{4} - x)}{cot 2 x}, x \neq \frac{π}{4} .

f (x)

is continuous at

x = \frac{π}{4},

then the value of

f (\frac{π}{4})

f (x) = \frac{1 - sin 2 x + cos 2 x}{2 cos 2 x}

α + β = \frac{5 π}{4} .

Then the value of

f (α) \cdot f (β)

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Identity (x+y)(x-y)

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