Let hn+1(x) = hn(x) + 1 , if n is odd;
= hn(x) + 2, if n is even;
If the minimum value of h1(x) is 1 , then what will be the minimum value of h100(x)?
option b
h1(x) = 1 h2(x) = 2
h3(x) = 4 h4(x) = 5
h5(x) = 7 h6(x) = 8
=> hn(x) =, when “n” is even
h100(x) = 149