Let h n -1 x - h n x -1- if n is odd- h n x -2- if n is even-If the minimum value of h 1 x is 1 - then what will be the minimum value of h 100 x -A- 149B- 150C- None of theseD- 100

The correct option is A 149option bh1(x) = 1 h2(x) = 2h3(x) = 4 h4(x) = 5h5(x) = 7 h6(x) = 8= gt ...

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Quantitative Aptitude

Functions

Let h n +1 x ...

Question

Let h_n+1(x) = h_n(x) + 1 , if n is odd;
= h_n(x) + 2, if n is even;
If the minimum value of h₁(x) is 1 , then what will be the minimum value of h₁₀₀(x)?

100

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149

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150

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None of these

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Solution

The correct option is B 149
option b
h₁(x) = 1 h₂(x) = 2
h₃(x) = 4 h₄(x) = 5
h₅(x) = 7 h₆(x) = 8
=> h_n(x) =, when “n” is even
h₁₀₀(x) = 149

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Let hn+1(x) = hn(x) + 1 , if n is odd; = hn(x) + 2, if n is even;If the minimum value of h1(x) is 1 , then what will be the minimum value of h100(x)?

The correct option is B 149option bh1(x) = 1 h2(x) = 2h3(x) = 4 h4(x) = 5h5(x) = 7 h6(x) = 8=> hn(x) =, when “n” is evenh100(x) = 149

Let h_n+1(x) = h_n(x) + 1 , if n is odd;
= h_n(x) + 2, if n is even;
If the minimum value of h₁(x) is 1 , then what will be the minimum value of h₁₀₀(x)?

The correct option is B 149
option b
h₁(x) = 1 h₂(x) = 2
h₃(x) = 4 h₄(x) = 5
h₅(x) = 7 h₆(x) = 8
=> h_n(x) =, when “n” is even
h₁₀₀(x) = 149