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Question

Let P=(1,0,1) Q=(1,2,0) R=(2,0,3) and S=(3,2,1), then the length of the components of RS on PQ is?

A
1/3
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B
2/3
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C
4/3
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D
5/3
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Solution

The correct option is C 4/3
RS=OSOR=^i2^j+2^kPQ=OQOP=2^i+2^j+^kPQ=(2)2+(2)2+(1)2=3

So, component of RS on PQ=|RS.PQ|PQ||

Component of RS on PQ =∣ ∣ ∣(^i2^j+2^k).(2^i+2^j+^k)3∣ ∣ ∣=43

Hence the option C is correct answer.

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