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Question

Let R={(x,y):x,yϵZ,y=2x4}. If (a, -2) and 4,b2)ϵR, then write the values of a and b.

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Solution

We have,

R = {(x,y):x,yϵZ,y=2x4}

Now,

y = 2x - 4

Putting y = - 2 and x = a, we get

-2 = 2a - 4

42=2a

2=2a

2a=2

a=22=1

Putting y=b2 and x = 4, we get

b2=2×44

b2=84

b2=4

b=±2

Hence, a=1,b=±2.


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