Let $U = {1, 2, 3, 4, 5, 6}$ $A = {2, 3}$ $B = {3, 4, 5}$ then $A^{'}$ and $B^{'}$

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Solution

We have,

$U = {1, 2, 3, 4, 5, 6}$

$A = {2, 3}$

$B = {3, 4, 5}$

Now,

$A^{'} = U - A$

$= {1, 2, 3, 4, 5, 6} - {2, 3}$

$A^{'} = {1, 4, 5, 6}$

$B^{'} = U - B$

$= {1, 2, 3, 4, 5, 6} - {3, 4, 5}$

$B^{'} = {1, 2, 6}$

Hence, this is the answer.

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