Let U be the universal set and A - B - C - U- Then -A - B - B - C - C - A- equals

Explanation for the correct option:(A – B) ∪ (B – C) ∪ (C – A) will majority of the parts except for A ∩ B ∩ C.So, [(A – B) ∪ (B – C) ∪ (C – A)]' = A ∩ B ...

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Byju's Answer

Standard XIII

Mathematics

Properties of Symmetric Difference of Sets

Let U be the ...

Question

Let $U$ be the universal set and $A \cup B \cup C = U$ . Then $[(A - B) \cup (B - C) \cup (C - A)]'$ equals

$A \cup B \cup C$

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$A \cap B \cap C$

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$A \cup (B \cap C)$

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$A \cap (B \cup C)$

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Solution

The correct option is B
$A \cap B \cap C$

Explanation for the correct option:
$(A - B) \cup (B - C) \cup (C - A)$ will majority of the parts except for $A \cap B \cap C$ .
So, $[(A - B) \cup (B - C) \cup (C - A)]' = A \cap B \cap C$
Hence, the correct option is (B)

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Let U be the universal set and A∪B∪C=U. Then [(A-B)∪(B-C)∪(C-A)]' equals

The correct option is B A∩B∩CExplanation for the correct option:(A–B)∪(B–C)∪(C–A) will majority of the parts except for A∩B∩C.So, [(A–B)∪(B–C)∪(C–A)]'=A∩B∩CHence, the correct option is (B)

Let $U$ be the universal set and $A \cup B \cup C = U$ . Then $[(A - B) \cup (B - C) \cup (C - A)]'$ equals

The correct option is B
$A \cap B \cap C$

Explanation for the correct option:
$(A - B) \cup (B - C) \cup (C - A)$ will majority of the parts except for $A \cap B \cap C$ .
So, $[(A - B) \cup (B - C) \cup (C - A)]' = A \cap B \cap C$
Hence, the correct option is (B)