Let y =12+13+12+13+....... What is the value of y?
y =12+13+12+13+.......
Thus y = 12+13+y
⟹y=(3+y)(6+2y+1)⇒2y2+7y=3+y. On solving, y=(−3±√15)2. Since the given fraction is positive, the value of y is (√15−3)2.
Let y=12+13+12+13+..... What is the value of y?