Let y=log(log(x)) .Then find the value of eydydx.
Compute the value of eydydx:
A function y=log(log(x)) is given.
Raise both sides to the power of the exponent.
So,
ey=elog(log(x))⇒ey=log(x)[∵elogx=x]
Now, differentiate both sides with respect to x.
eydydx=1x.
Hence, the value of eydydx is 1x.