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Question

lf y=eacos1x then (1x2)y′′xy=

A
ay
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B
a2y
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C
ay
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D
a2y
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Solution

The correct option is D a2y
y1=eacos1x(a1+x2)

y11=eacos1x(a1+x2)+eacos1x⎜ ⎜ ⎜ ⎜ax(1x2)32⎟ ⎟ ⎟ ⎟

(1x2)y′′=a2y+yx

(1x2)y′′yx=a2y

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