limx→1x15−1x10−1
limx→1x15−1x10−1
=limx→1x15−1x−1x10−110x−1 [Dividing numerator and denominator by (x-1)]
=limx→1x15−115x−1limx→1x10−110x−1
Applying the formula limx→axn−anx−a=nan−1 in numerator and denominator
⇒limx→1x15−115x−1limx→1x10−110x−1=15(1)15−110(1)10−1
=1510=32
Hence, answer is 32