log2* log1/2* log3x>0. find x

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{log}_{2} {log}_{3} x > 0,

x

f (x) = \frac{l o g \frac{1}{2} + l o g (2 + 4 x)}{x}

x \neq 0

2 {log}_{2} ({log}_{2} x) + {log}_{\frac{1}{2}} ({log}_{2} 2 \sqrt{2} x) = 1

{log}_{1 / 2} (x + 1) > {log}_{2} (2 - x)

{log}_{3} ({log}_{2} x) + {log}_{1 / 3} ({log}_{1 / 2} x) = 1

x

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