m distinct animals of a circus have to be placed in m cages, one in each cage. If n(< m) cages are too small to accomoodate p(n < p < m) animals, then the number of ways of putting the animals in to cages are
A
(m−nPp)(m−pPm−p)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
m−nCp
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(m−nCp)(m−pCm−p)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B(m−nPp)(m−pPm−p) Number of ways of arranging p big animals into m n big cages =m−npp. Now remaining animals can be arranged in any cage in n−pPm−p ways ∴ Desired number of ways =m−nPp×m−pPm−p