Question

Match List 1 with List 2

Answer 1

Van der Waals Equation of State for a Real Gas:
$(P+\frac{a}{V^2})(V-b)=RT$
In thermodynamics, the Boyle temperature is the temperature at which a non ideal gas behaves most like an ideal gas. At Boyle temperature, At the Boyle temperature, T = TB and Z = 1
$T_B=a/Rb$
At the critical point, only one phase exists. The heat of vaporization is zero and
$(\delta P/\delta V{)}_T=0$
by solving $T_c=8a/27Rb$
$P_c=a/27b^2$
Every gas have inversion temperature, below which gas shows cooling and above which gas shows heating by subjecting J.T. effect
and $T_i=2a/Rb$