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B
cot73∘
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C
sin52∘
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D
cos26∘
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Solution
From complementary relation we have sinθ=cos(90∘−θ) and vice versa tanθ=cot(90∘−θ) and vice versa
Hence, tan17∘=cot(90∘−17∘)=cot73∘
Similarly, cot43∘ = tan47∘ cos38∘ = sin52∘ sin64∘ = cos26∘