Metamers of ethyl propionate are:

C_{4} H_{9} C O O H and H C O O C_{4} H_{9}

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C_{4} H_{9} C O O H and C H_{3} C O O C_{3} H_{7}

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C H_{3} C O O C H_{3} and C H_{3} C O O C_{3} H_{7}

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C H_{3} C O O C_{3} H_{7} and C_{3} H_{7} C O O C H_{3}

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Solution

The correct option is D $C H_{3} C O O C_{3} H_{7} and C_{3} H_{7} C O O C H_{3}$
Compounds having the same molecular formula but different number of carbon atoms on either side of functional groups are known as metamers.

Metamers of ethyl propionate are:

Hence correct answer is (d).

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