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Byju's Answer
Standard XII
Mathematics
Basic Inverse Trigonometric Functions
Minimum value...
Question
Minimum value of
9
sin
2
y
+
3
cos
2
x
+
4
sec
2
x
+
4
csc
2
y
is
Open in App
Solution
Minimum value of
9
s
i
n
2
y
+
3
c
o
s
2
x
+
4
s
e
c
2
x
+
4
c
s
c
2
y
.
⇒
(
9
s
i
n
2
y
+
4
c
o
s
2
y
)
+
3
c
o
s
2
x
+
4
s
e
c
2
x
⇒
2
√
9
×
4
+
2
√
3
×
4
=
2
×
3
×
2
+
2
×
2
×
√
3
12
+
4
√
3
=
4
√
3
+
12
short trick
a
s
i
n
2
θ
+
b
c
o
s
e
c
2
θ
a
c
o
s
2
θ
+
b
s
e
c
2
θ
a
t
a
n
2
θ
+
b
c
o
t
2
θ
(1) Minimum value
=
2
√
a
b
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