Question

A transistor is connected in common emitter circuit configuration, the collector supply voltage is $10\text{V}$ and the voltage drop across a resistor of $1000\Omega$ in the collector circuit is $0.6\text{V}$. If the current gain factor $\left(\beta \right)$ is $24$, then the base current is _____ $\mu \text{A}$.
(Round off to the Nearest Integer)

Answer 1

Given:
$R=1000\Omega ;\beta =24$
$V_R=0.6\text{V};V_C=10\text{V}$

So, collector current,

$I_C=\frac{V_R}{R}=\frac{0.6}{1000}=6\times {10}^{-4}\text{A}$

And we know that,

Current gain factor, $\beta =\frac{I_C}{I_B}=24$

$\therefore I_B=\frac{I_C}{\beta }=\frac{6\times {10}^{-4}}{24}=25\mu \text{A}$

$\text{Correct answer}:25$