For an electrochemical cell Sns-Sn2- aq-1M-Pb2- aq- 1M-Pbs- the ratio -Sn2-Pb2- when this cell attains equilibrium is -Given - ESn2-Sn0-0-14 V- EPb2-Pb0-0-13 V- 2-303RTF-0-06

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Nersnt Equation

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Question

For an electrochemical cell $S n (s) | S n^{2 +} (a q, 1 M) | | P b^{2 +} (a q, 1 M) | P b (s)$ , the ratio $\frac{[S n^{2 +}]}{[P b^{2 +}]}$ when this cell attains equilibrium is ____.
(Given : $E_{S n^{2 +} | S n}^{0} = - 0.14 V, E_{P b^{2 +} | P b}^{0} = - 0.13 V, \frac{2.303 R T}{F} = 0.06$ )

2.15

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S n (s) | S n^{2 +} (a q ., 1 M) | | P b^{2 +} (a q ., 1 M) | P b (s)

\frac{[S n^{2 +}]}{[P b^{2 +}]}

E_{\frac{S n^{2 +}}{S n}}^{\circ} = - 0.14 V; E_{\frac{P b^{2 +}}{P b}}^{\circ} = - 0.13 V, \frac{2.303 R T}{F} = 0.06 V)

E^{0}

S n | S n^{2 +} (1 M) | | P b^{2 +} (10^{- 3} M) | P b, E^{0} (S n^{2 +} | S n) = - 0.14 V E^{0} (P b^{2 +} | P b) = - 0.13

P b^{2 +}

S n^{2 +}

S n (s) + P b^{2} (a q .) \to S n^{2 +} (a q .) + P b (s)

E_{S n^{2 +} / S n}^{\circ} = - 0.136 v o l t

E_{P b^{2 +} / P b}^{\circ} = - 0.126 v o l t

P b + S n^{2 +} \to P b^{2 +} + S n

\frac{[P b^{2 +}]}{[S n^{2 +}]}

E_{c e l l} = 0

E_{P b / P b^{2 +}}^{\circ} = 0.13 v o l t

E_{S n^{2 +} / S n}^{\circ} = - 0.14 v o l t

E^{0}

E

S n | {S n}^{2 +} (1 M) ∥ {P b}^{2 +} (10^{- 3} M) | P b, E^{0} ({S n}^{2 +} / S n) = - 0.14 V, E^{0} ({P b}^{2 +} / P b) = - 0.13 V

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