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Question

A 200 V shunt motor takes 10 A when running on no load. At higher loads the brush drop is 2 V and at light loads it is negligible. The stray load loss at a line current of 100 A is 50% of no load loss. If armature and field resistance is 0.2 Ω and 100 Ω respectively, then the power loss in the motor is ____kW
  1. 5.1

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Solution

The correct option is A 5.1
No load loss = 200 x 10 = 2000 W

If=200100=2A

Core loss =(200×8)+(82×0.2)

=1587.2W



At load :
Stray load loss = 0.5 x 2000 = 1000 W


PL=(I2aRa+VbrushIa+Pstray)+(Pcore+Pshunt field)

PL=(982×0.2)+(2×98)+1000+1587.2+(200×2)

PL=5.104 kW

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