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Question
The dipole moment of KCl is 3.336×10−29 Coulomb meters which indicates that it is a highly polar molecule. The interionic distance between K+ and Cl− in this molecule is 2.6×10−10 m. The percentage ionic character of KCl molecule, if there were opposite charges of one fundamental unit located at each nucleus is:
The dipole moment of KCl is 3.336×10−29 Coulomb meters which indicates that it is a highly polar molecule. The interionic distance between K+ and Cl− in this molecule is 2.6×10−10 m. The percentage ionic character of KCl molecule, if there were opposite charges of one fundamental unit located at each nucleus is:
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Solution
The correct option is C 80.2%
Dipole moment is calculated theoretically as:
μ=q×d
where, μ = dipole moment
q = charge on ions
d = distance between charges
Here, q=1.6×10−19 C and d=2.6×10−10 m
μtheo=(1.6×10−19)×(2.6×10−10)
= 4.16×10−29 Cm
and μobs=3.336×10−29 Coulomb meters
% ionic character = μobsμtheo×100
= 3.336×10−294.16×10−29×100
= 80.2%
Dipole moment is calculated theoretically as:
μ=q×d
where, μ = dipole moment
q = charge on ions
d = distance between charges
Here, q=1.6×10−19 C and d=2.6×10−10 m
μtheo=(1.6×10−19)×(2.6×10−10)
= 4.16×10−29 Cm
and μobs=3.336×10−29 Coulomb meters
% ionic character = μobsμtheo×100
= 3.336×10−294.16×10−29×100
= 80.2%
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