The number of A in Tp such that A is either symmetric or skew-symmetric or both, and det(A) divisible by p is
A
(p−1)2
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B
2p−1
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C
(p−1)2+1
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D
2(p−1)
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Solution
The correct option is B2p−1 If A is skew-symmetric, |A|=–b2 ∴|A| if b=0 in which case A is symmetric.
If A is [abba],|A|=a2−b2 ∴p|A| if either p|a+b or p|a–b.
The second case occurs only when a=b which gives p choices. The first case again gives p choices with a=0=b counted again. ∴ The number of such matrices is 2p–1.