What will be the values of the coefficients x, y and z if the given reaction is balanced?

${xFeCl}_{3} + yMgO 🡪 {Fe}_{2} O_{3} + {zMgCl}_{2}$

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Solution

To find the value of x, y and z, we need to balance the given equation.

Number of Fe atoms on the reactant side: 1
Number of Fe atoms on the product side: 2
So we will multiply 2 on the left side to $F e C l_{3}$ .
Hence it will become; 2

$F e C l_{3} + M g O 🡪 F e_{2} O_{3} + M g C l_{2}$

Number of Cl atoms on the reactant side: 6 (i.e. 2x3 )
Number of Cl atoms on the product side: 2
So we will multiply 3 on the right side to MgCl2.
Hence it will become;

$2 F e C l_{3} + M g O 🡪 F e_{2} O_{3} + 3 M g C l_{2}$
Now, the number of Mg atoms are not balanced. In order to balance it, we will multiply 3 to MgO.

$2 F e C l_{3} + 3 M g O 🡪 F e_{2} O_{3} + 3 M g C l_{2}$
From the above-balanced equation the value of x, y and z are 2, 3, and 3 respectively.

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