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Question

A stone is thrown vertically upwards with an initial velocity of 25 m/s. The maximum height reached by the stone is
[Take g=10 m/s2]

A
11.5 m
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B
20.15 m
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C
31.25 m
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D
5.75 m
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Solution

The correct option is C 31.25 m
When the stone reaches the highest point, its velocity becomes zero.
v=0
Also,
u=25 m/s and
a=g=10 m/s2
Applying, v2=u2+2as
02=(25)2+2×(10)×s
or, s=25×2520 s=31.25 m

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