A stone is thrown vertically upwards with an initial velocity of 25m/s. The maximum height reached by the stone is [Take g=10m/s2]
A
11.5m
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B
20.15m
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C
31.25m
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D
5.75m
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Solution
The correct option is C31.25m When the stone reaches the highest point, its velocity becomes zero. ⇒v=0
Also, u=25m/s and a=−g=−10m/s2
Applying, v2=u2+2as ⇒02=(25)2+2×(−10)×s
or, s=25×2520⇒s=31.25m