Question

The solubility of carbon dioxide is$3.48\text{g/L}$ in water at $0^{\circ }\text{C}$ and $1.00\text{atm}$. The solubility of carbon dioxide in water at $0^{\circ }\text{C}$ and a pressure of $3.0\text{atm}$ is

• A. 10.43
• B. 10.44

Answer 1

Answer: (A), (B)

The solubility of carbon dioxide gas is proportional to the pressure of the gas above the liquid.
$P_1=1\text{atm}\text{Solubility},S_1=3.48\text{g/L}{P}_2=3\text{atm}{S}_2=?$

From Henry's law,
$P_{gas}=K_H{X}_{gas}$
where, $X_{gas}=\text{mole fraction of gas in liquid}$
$P_{gas}\text{is the partial pressure of gas over liquid surface}$
$K_H$ is constant at same temperature
So,
$\text{Solubility}\propto \text{pressure}$

$\frac{S_1}{S_2}=\frac{P_1}{P_2}\Rightarrow \frac{3.48\text{g/L}}{S_2}=\frac{1}{3}$
$\Rightarrow S_2\text{(solubility at 3 atm) =}\frac{3}{1}\times 3.48$
$=10.44\text{g/L}$