Of the following four aqueous solution, total number of those solutions whose freezing point is lower than that of $0.10 M C_{2} H_{5} O H$ is/are (integer answer)
$(i) 0.10 M B a_{3} (P O_{4})_{2} (i i) 0.10 M N a_{2} S O_{4} (i i i) 0.10 M K C l (i v) 0.10 M L i_{3} P O_{4}$

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Solution

$i f o r C_{2} H_{5} O H i s 1.$

$Δ T_{f} = i k_{f} m$

$Δ T_{f} = i (considering molarity = molality)$

$B a_{3} (P O_{4})_{2} H_{2} O - - \to 3 B a^{2 +} + 2 P O_{4}^{3 -} i = 5$

$N a_{2} S O_{4} H_{2} O - - \to 2 N a^{+} + S O_{4}^{2 -} i = 3$

$K C l H_{2} O - - \to K^{+} + C l^{-} i = 2$

$L i_{3} P O_{4} H_{2} O - - \to 3 L i^{+} + P O_{4}^{3 -} i = 4$
Value for freezing point will be lower for that solutions which have higher value of van't Hoff factor than $C_{2} H_{5} O H$
Here all have higher value of $i$ than $C_{2} H_{5} O H$
So, answer is 4

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Of the following four aqueous solution, total number of those solutions whose freezing point is lower than that of $0.10 M C_{2} H_{5} O H$ is/are (integer answer)
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