A car of mass m starts from rest and accelerates so that the instantaneous power delivered to the car has a constant magnitude P0. The instantaneous velocity of this car is proportional to
A
t−1/2
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B
t1/2
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C
t/√m
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D
t2P0
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Solution
The correct option is Bt1/2 Power delivered can be given as (F.v) where, F is the force applied and v is the velocity of the car.
Or, we can write it as [(ma).v]
Or, P0=m(dvdt)v
Or, vdv=(P0m)dt
On integrating both sides we get, v22=P0mt
Thus, we can say v∝√t.
Hence, option (C) is correct.