~(p∨q)∨(~p∧q)is logically equivalent to
~p
p
q
~q
Explanation for the correct option:
Finding ~(p∨q)∨(~p∧q)is logically equivalent to:
~p∨q∨(~p∧q)(~p∧~q)∨(~p∧q)~p∧(~q∨q)[∵p∧(q∨r)=(p∧q)∨(p∧r)]∴~p∧(~q∨q)≅~p[IfqisT~qisF⇒~q∨q≅T]
Hence the correct answer is option (A)