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Byju's Answer
Standard XII
Mathematics
Multinomial Theorem
Number of pos...
Question
Number of positive integral solutions of
15
<
x
1
+
x
2
+
x
3
≤
20
is
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Solution
15
<
x
1
+
x
2
+
x
3
≤
20
⇒
x
1
+
x
2
+
x
3
=
16
+
r
r
=
0
,
1
,
2
,
3
,
4
Now number of positive integral solution of
⇒
x
1
+
x
2
+
x
3
=
16
+
r
is
16
+
r
−
1
C
3
−
1
=
15
+
r
C
2
Thus required number of solutions
=
4
∑
r
=
0
15
+
r
C
2
=
15
C
2
+
16
C
2
+
17
C
2
+
18
C
2
+
19
C
2
=
685
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Multinomial Theorem
Standard XII Mathematics
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