You visited us 2 times! Enjoying our articles? Unlock Full Access!

Valency and Oxidation State

On complete r...

Question

On complete reaction of $F e C l_{3}$ with oxalic acid in an aqueous solution containing $K O H$ , resulted in the formation of product A. The secondary valency of $F e$ in the product A is (Round off to the Nearest Integer)

Open in App

Solution

Answer :6
$F e C l_{3} + 3 H_{2} C_{2} O_{4} + 6 K O H \to K_{3} [F e (C_{2} O_{4})_{3}] A + 3 K C l + 6 H_{2} O$
The secondary valency is the number of ions of molecules that are coordinated to the metal ion or it is the number of ligands attached or coordinated to metal ions.

Here secondary valency is 6

Suggest Corrections

Similar questions

A g N O_{3}

m L

F e^{2 +}

m L

M

C r_{2} {O_{7}}^{2 -}

F e^{2 +}

\times 10^{- 2}

M

N a N O_{3}

50 m L

m g

N a^{+}

m L

g

g m o l^{- 1}

N a N O_{3}

N a^{+}

g m o l^{- 1} [N a : 23; N : 14; O : 16]

25

F e_{2} (S O_{4})_{3} . (N H_{4})_{2} . S O_{4} .24 H_{2} O

1.25

F e + F e_{2} (S O_{4})_{3} ⟶ 3 F e S O_{4}

0.107 N

K M n O_{4}

F e

Join BYJU'S Learning Program