One of the factor of $Y^{2} - 7 Y + 12$ is

(Y - 3)

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(Y + 3)

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(Y + 4)

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(Y - 2)

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Solution

The correct option is A $(Y - 3)$
$Y^{2} - 7 Y + 12$
$= Y^{2} - 3 y - 4 Y + 12$
$= Y (Y - 3) - 4 (Y - 3)$
$= (Y - 3) (Y - 4)$
$\Rightarrow Y - 3$ is a factor of $Y^{2} - 7 Y + 12$

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Similar questions

y^{2} + 7 y + 12

Factorise the quadratic polynomial by splitting the middle term: y² - 4 y –21

Factorization:

$9 (2 x - 3 y)^{2} - 12 (2 x - 3 y) (2 x + 3 y) + 4 (2 x + 3 y)^{2}$

g (y)

f (y)

f (y) = 3 y^{4} + 5 y^{3} - 7 y^{2} + 2 y + 2

g (y) = y^{2} + 3 y + 1

y^{2} - 7 y + 12

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