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Question

One of the factors of x2+1x2+2−2x−2x is:

A
x1x
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B
x1x1
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C
x+1x
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D
x2+1x2
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Solution

The correct option is C x+1x
We can use the identity a2+2ab+b2=(ab)2 we can simplify the expression as follows.

x2+1x2+22x2x
=(x2+1x2+2)2(x+1x)
=(x+1x)22(x+1x)
=(x+1x)(x+1x2)

Thus, the factors of x2+1x2+22x2x are
(x+1x) and (x+1x2).

Among these (x+1x) is there in options.

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