Question

Out of $H_{2}Oand{H}_{2}S$ Which one has a higher bond angle and why?

Answer 1

Bond angle based on electronegativity of oxygen and sulphur

Bond angle in $H_{2}O$ is more because oxygen is more electronegative than Sulphur.

As compared to $H_{2}S$ the O atom is more electronegative in $H_{2}O$ than S in $H_{2}S$.

This high electronegativity of Oxygen attracts the bond pair electrons towards itself much closer than in case of $H_{2}S$.

Thus, electrons of O-H bond come closer and experience maximum repulsion due to which these bonds tend to go away from each other as much as possible.

But in $H_{2}S$, electronegativity of S atom is much less and H-S bond electrons do not come much closer and not suffer much repulsion and hence bond angle is less for $H_{2}S$ in comparison to $H_{2}O$.