You visited us 1 times! Enjoying our articles? Unlock Full Access!

Multiplication of Any Polynomial

p+2 qp-q=p2+p...

Question

$(p + 2 q) (p - q)$ = $p^{2} + p q$ - _____

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
(p + 2q)(p - q), by using distributive property p(p - q) + 2q(p - q) = $p^{2}$ - pq + 2pq - 2 $q^{2}$ = $p^{2}$ + pq - 2 $q^{2}$ ≠ $p^{2}$ - 2 $q^{2}$

Suggest Corrections

Similar questions

p q x^{2} - (p^{2} + q^{2}) x + p q = 0,

x

(p + 2 q) (p + 3 q)

p = 1

q = 0

P

Q

P Q = 0 \Rightarrow 1) P = 0

Q = 0

b o t h

P Q = I_{2} \Rightarrow P = Q^{- 1}

(P + Q)^{2} = P^{2} + 2 P Q + Q^{2}

2 \times 2

P Q = O \Rightarrow P = O

Q = O

P Q = I_{2} \Rightarrow P = Q^{- 1}

{(P + Q)}^{2} = P^{2} + 2 P Q + Q^{2}

Let p and q are distinct naturals such that 2005+p=q² and 2005+q=p².Find the value of 2014+pq

Join BYJU'S Learning Program