ACAR STARTS FROM REST AND MOVES ALONG X-AXIS W ITH CONSTANT ACCELERATION 5ms2 FOR 8SEC.IF IT THEN ACCELERATES WITH CONSTANT VELOCITY,WHAT DISTANCE WILL THE CAR COVER IN 12 SEC SINCE IT STARTED FROM REST?
ACAR STARTS FROM REST AND MOVES ALONG X-AXIS W ITH CONSTANT ACCELERATION 5ms2 FOR 8SEC.IF IT THEN ACCELERATES WITH CONSTANT VELOCITY,WHAT DISTANCE WILL THE CAR COVER IN 12 SEC SINCE IT STARTED FROM REST?
There seems to be some error in the equation. The car first accelerates with 5 ms-2 then it accelerates with constant velocity. It should have been, then it continues with constant velocity.
So, the car moves from rest with acceleration 5 ms-2 for 8 s.
Distance travelled in this time is, S1 = ut + ½ at2
=> S1 = 0 + ½ × 5 × 82
=> S1 = 160 m
The velocity it attains in this 8 s is,
v = u + at
=> v = 0 + 5 × 8 = 40 m/s
So, distance travelled with this velocity for another 4 s (12-8 = 4) is, S2 = 40 × 4 = 160 m
So, the total distance travelled by the car is = S1 + S2 = 160 + 160 = 320 m
There seems to be some error in the equation. The car first accelerates with 5 ms-2 then it accelerates with constant velocity. It should have been, then it continues with constant velocity.
So, the car moves from rest with acceleration 5 ms-2 for 8 s.
Distance travelled in this time is, S1 = ut + ½ at2
=> S1 = 0 + ½ × 5 × 82
=> S1 = 160 m
The velocity it attains in this 8 s is,
v = u + at
=> v = 0 + 5 × 8 = 40 m/s
So, distance travelled with this velocity for another 4 s (12-8 = 4) is, S2 = 40 × 4 = 160 m
So, the total distance travelled by the car is = S1 + S2 = 160 + 160 = 320 m
