the density of ice is 0.9 g/cm³. When it floats in water, what fraction of its volume will remain above surface?

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Solution

$F r a c t i o n o f v o l u m e o f i c e a b o v e t h e w a t e r s u r f a c e i s g i v e n b y : 1 - \frac{v_{s}}{V_{0}} w h e r e v_{s} i s t h e v o l u m e o f o b j e c t i n w a t e r a n d V_{0} i s t h e v o l u m e o f t h e o b j e c t \frac{v_{s}}{V_{0}} = \frac{S_{0}}{S_{l}} w h e r e s_{0} i s t h e s p e c i f i c g r a v i t y o f o b j e c t a n d s_{l} i s t h e s p e c i f i c g r a v i t y o f l i q u i d s_{0} = \frac{d e n s i t y o f o b j e c t}{d e n s i t y o f w a t e r} s_{l} = \frac{d e n s i t y o f l q u i d}{d e n s i t y o f w a t e r} w h e n o b j e c t i s i c e a n d l i q u i d i s w a t e r s_{0} = 0.9 s_{l} = 1 v o l u m e a b o v e t h e s u r f a c e = 1 - \frac{0.9}{1} = 0.1$

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the density of ice is 0.9 g/cm3. When it floats in water, what fraction of its volume will remain above surface?

the density of ice is 0.9 g/cm³. When it floats in water, what fraction of its volume will remain above surface?