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Complementary Ratios

Prove that co...

Question

Prove that cosA sin $(90^{\circ} - A)$ = 1 - $s i n^{2} A$

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Solution

L.H.S = cosA sin $(90^{\circ} - A)$ = cos A. cosA = $c o s^{2} A$

= 1 - $s i n^{2} A$ = RHS

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\frac{cos A}{sin (90^{\circ} - A)} + \frac{sin A}{cos (90^{\circ} - A)} = 2

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